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NEW QUESTION 28
The colonies seen growing on the bird seed agar appear smooth and have a distinct reddish-brown pigmentation. The active ingredient in bird seed (Guizotia abyssinica) agar is caffeic acid, which is extracted and placed in an agar containing 1% glucose. Of the cryptococci, and other species of yeasts, Cryptococcus neoformans selectively produces the enzyme phenoloxidase, which oxidizes the caffeic acid in the medium to melanin, producing the red-brown pigmentation.
The other yeast species included in this exercise do not possess phenoloxidase activity and therefore remain non-pigmented when grown on bird seed agar.
The colonies shown in this photograph were grown on Guizotia abyssinica (bird seed) agar at 30°C for 72 hours. The most likely identification is:

• A. Cryptococcus neoformans
• B. Saccharomyces cerevisiae
• C. Candida parapsilosis
• D. Cryptococcus laurentii

Answer: A

NEW QUESTION 29
Heinz bodies occur as the result of denaturation and precipitation of hemoglobin, and are often attached to the red cell membrane. They require staining with crystal violet or methyl violet to be visible. They may be seen in thalassemia, with unstable hemoglobins, or during a hemolytic episode in G6PD deficiency.
Hematology
The intracellular precipitates seen in the RBCs in this illustration is termed:

• A. Dohle bodies
• B. Heinz bodies
• C. Reticulocytes
• D. May-Hegglin anomaly

Answer: B

NEW QUESTION 30
Which of the following agencies administers the certification test that you will be eligible to take at the end of your 4 semester?

• A. AAMA
• B. ASCP
• C. ASPT
• D. AARP

Answer: B

NEW QUESTION 31
Failure to deliver glucose drawn in a serum separator tube (SST) to the laboratory within the recommended time will cause:
Question options:

• A. glycolysis
• B. both A and C
• C. a falsely increased glucose value
• D. a falsely decreased glucose value

Answer: B

NEW QUESTION 32
The creatinine clearance for this patient is 100 mL/min.
Creatinine clearance values are calculated using the following equation:
Creatinine Clearance (mL / min) = (Urine Creatinine / Serum Creatinine) x Urine Volume (mL) / [ time (hr) x
60 ]
For this patient Creatinine clearance (mL/min)= (120/1.5) x (1800 / [24 x 60])
80 x 1800/1440, which is 80 x 1.25, or 100 mL/min
A 45-year-old male of average height and weight had a serum creatinine of 1.5 mg/dL and urine creatinine was
120 mg/dL; the total volume of urine collected over a 24-hour period was 1,800 mL. Calculate the creatinine clearance for this patient in mL/min.

• A. 0
• B. 1
• C. 2
• D. 3
• E. 4

Answer: C

NEW QUESTION 33
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